Modulus math
No edit summary
(Replacing message template with parser tag)
 
(4 intermediate revisions by 2 users not shown)
Line 1: Line 1:
In C#, do 5%3 to get the rest of the division 5/3.
<message>Write the content here to display this box</message>
In C#, do 5%3 to get the rest of the division 5/3. In OCL, you can do 5.IEEERemainder( 3 )


In OCL, you can do 5.IEEERemainder( 3 )
(Please note that modulus and remainder are not mathematically equivalent.  


(Please note that modulus and remainder are not mathematically equivalent. See: https://rob.conery.io/2018/08/21/mod-and-remainder-are-not-the-same/)
See also: https://rob.conery.io/2018/08/21/mod-and-remainder-are-not-the-same/)


See also: [https://docs.microsoft.com/en-us/dotnet/api/system.math.ieeeremainder IEEERemainder documentation in .net]
See also: [https://docs.microsoft.com/en-us/dotnet/api/system.math.ieeeremainder IEEERemainder documentation in .net]
[[Category:OCL]]
[[Category:OCL]]
[[Category:C-Sharp]]
[[Category:C-Sharp]]
{{Edited|July|12|2024}}

Latest revision as of 07:46, 17 June 2024

In C#, do 5%3 to get the rest of the division 5/3. In OCL, you can do 5.IEEERemainder( 3 )

(Please note that modulus and remainder are not mathematically equivalent.

See also: https://rob.conery.io/2018/08/21/mod-and-remainder-are-not-the-same/)

See also: IEEERemainder documentation in .net

This page was edited 95 days ago on 06/17/2024. What links here